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A stone tied to a rope is rotated in a v...

A stone tied to a rope is rotated in a vertical circle with uniform speed. If the difference between the maximum and minimum tensions in the rope is 20 N, mass of the stone in kg is (take, g= 10 `ms^(-2)`)

A

`0.75`

B

`1.0`

C

`1.5`

D

`0.5`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the mass of the stone based on the difference in maximum and minimum tensions in the rope when the stone is rotated in a vertical circle. ### Step-by-Step Solution: 1. **Understanding the Forces**: - At the lowest point of the circle (point B), the tension (T_max) in the rope is at its maximum. The forces acting on the stone are: - The gravitational force (weight) acting downwards: \( mg \) - The centripetal force required to keep the stone moving in a circle, which is provided by the tension in the rope: \( T_{max} = mg + \frac{mv^2}{l} \) - At the highest point of the circle (point A), the tension (T_min) in the rope is at its minimum. The forces acting on the stone are: - The gravitational force (weight) acting downwards: \( mg \) - The centripetal force is now provided by the difference between the tension and the weight: \( T_{min} = \frac{mv^2}{l} - mg \) 2. **Setting Up the Equations**: - From the above points, we have: - \( T_{max} = mg + \frac{mv^2}{l} \) (Equation 1) - \( T_{min} = \frac{mv^2}{l} - mg \) (Equation 2) 3. **Finding the Difference in Tensions**: - The difference between the maximum and minimum tensions is given as: \[ \Delta T = T_{max} - T_{min} \] - Substituting the expressions from Equations 1 and 2: \[ \Delta T = \left( mg + \frac{mv^2}{l} \right) - \left( \frac{mv^2}{l} - mg \right) \] - Simplifying this: \[ \Delta T = mg + \frac{mv^2}{l} - \frac{mv^2}{l} + mg = 2mg \] 4. **Using the Given Information**: - We know from the problem statement that the difference in tensions is \( \Delta T = 20 \, N \): \[ 2mg = 20 \] - Rearranging this gives: \[ mg = 10 \] 5. **Finding the Mass of the Stone**: - Given \( g = 10 \, m/s^2 \), we can find the mass \( m \): \[ m = \frac{mg}{g} = \frac{10}{10} = 1 \, kg \] ### Final Answer: The mass of the stone is \( 1 \, kg \).

To solve the problem, we need to find the mass of the stone based on the difference in maximum and minimum tensions in the rope when the stone is rotated in a vertical circle. ### Step-by-Step Solution: 1. **Understanding the Forces**: - At the lowest point of the circle (point B), the tension (T_max) in the rope is at its maximum. The forces acting on the stone are: - The gravitational force (weight) acting downwards: \( mg \) - The centripetal force required to keep the stone moving in a circle, which is provided by the tension in the rope: \( T_{max} = mg + \frac{mv^2}{l} \) ...
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