A particle moving in uniform circle makes 18 revolutions in 1 minutes. If the radius of the circle is 10 cm, the speed of the particle is

Options

A. `3pixx10^(-2)ms^(-1)`
B. `4pixx10^(-2)ms^(-1)`
C. `5pixx10^(-2)ms^(-1)`
D. `6pixx10^(-2)ms^(-1)`

Answer

D

Explanation

Given, n = 18 per minute `=(18xx2pi)/(60)` and r = 10 cm
We know that `v=r omega`
Here, `v=0.1xx(18xx2pi)/(60)`
`v=3xx2pixx10^(-2)rArrv=6pixx10^(-2)ms^(-1)`