An electric field of `10^5 N//C` points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of `+2muC and -5muC` at this spot?

The electric field due to a point charge at a distance 6 m from it is 630 N/C. The magnitude of the charge is

Two horizontal forces of magnitudes of 10N and P N act on a particle. The force of magnitude 10N acts due west and the force of magnitude P N acts on a bearing of 30^(@) east of north as shown in (figure) The resultant of these two force acts due north. Find the magnitude of the resultant.

Four point charges are placed at the corners of a square ABCD of side 10 cm, as shown in figure. The force on a charge of 1muC placed at the centre of square is

find the electric field strength due to a point charge of 5 muC at a distance of 80 cm from the charge.

Calculate the magnitude and direction of the electric field at a point P which is 30 cm to the right of a point charge Q = -3.0 xx 10^(-6) C

Electric charges of +10 muC,+5 muC,-3 muC and +8 muC are placed at the corners of a square of side sqrt(2) m, the potential at the centre of the square is

The electric force experienced by a charge of 5xx10^(-6) C is 25xx10^(-3) N . Find the magnitude of the electric field at that position of the charge due to the source charges.

Two point charges of 1muC and -1muC are separated by a distance of 100 Å. A point P is at a distance of 10 cm from the midpoint and on the perpendicular bisector of the line joining the two charges. The electric field at P will be

The force of attractions between two charges 8muC and -4muC is 0.2 N. Find the distance of separation.

A parallel plate capacitor has an electric field of 10^(5)V//m between the plates. If the charge on the capacitor plate is 1muC , then force on each capacitor plate is-