Electric field strength due to a point charge of `5 mu C` at a distance 80 cm from the charge is

find the electric field strength due to a point charge of 5 muC at a distance of 80 cm from the charge.

The electric field due to a point charge at a distance 6 m from it is 630 N/C. The magnitude of the charge is

Two charges, each of 5 mu C but opposite in sign, are placed 4 cm apart. Calculate the electric field intensity of a point that is a distance 4 cm from the mid point on the axial line of the dipole.

A combination of capacitors is set up as shown in the figure. The magnitude of the electric field, due to a point charge Q (having a charge equal to the sum of the charges on the 4 mu F and 9 mu F capacitors), at a point distance 30 m from it, would equal:

The electric field due to a charge at a distance of 3 m from it is 500 NC^(-1) . The magnitude of the charge is [(1)/(4 pi epsi_(0)) = 9 xx 10^(9) N - m^(2)//C^(2)]

The electric intensity due to a dipole of length 10 cm and having a charge of 500 muC , at a point on the axis at a distance 20 cm from one of the charges in air is

Two charges +20 mu C and - 20 muC are 5 mm apart. Find the electric field on axial as well as on the equatorial line at a distance 20 cm from the mid -point of the dipole.

A charge of mass .m. charge .2e. is released from rest in a uniform electric field of strength .E.. The time taken by it to travel a distance .d. in the field is

Suppose that electric potential due to a small charge configuration varies inversely with with square of distance from the charge distribution . Electric field intensity will vary inversely with what power of distance from the charge configuration in this case ?

Assertion: On going away from a point charge or a small electric dipole, electric field decreases at the same rate in both the cases Reason: Electric field is inversly proportional to square of distance from the charge or an electric dipole.