A conductor has `14.4 xx 10^(-19)` coulombs positive charge. The conductor has : (Charge on electron `= 1.6 xx 10^(-19)` coulombs

Options

A. 9 electrons in excess
B. 27 electrons in short
C. 27 electrons in excess
D. 9 electrons in short

Answer

To solve the problem, we need to determine how many electrons are missing from the conductor that has a positive charge of \( 14.4 \times 10^{-19} \) coulombs. The charge of a single electron is given as \( 1.6 \times 10^{-19} \) coulombs.

### Step-by-Step Solution:

1. **Identify the total positive charge of the conductor:**
\[ Q = 14.4 \times 10^{-19} \text{ coulombs} \]

2. **Identify the charge of a single electron:**
\[ e = 1.6 \times 10^{-19} \text{ coulombs} \]

3. **Use the formula to find the number of missing electrons (n):**
The relationship between total charge (Q), number of electrons (n), and charge of an electron (e) is given by:
\[ Q = n \times e \]
Rearranging the formula to find n gives:
\[ n = \frac{Q}{e} \]

4. **Substitute the values into the equation:**
\[ n = \frac{14.4 \times 10^{-19}}{1.6 \times 10^{-19}} \]

5. **Calculate n:**
\[ n = \frac{14.4}{1.6} = 9 \]

6. **Interpret the result:**
Since the conductor has a positive charge, it indicates that there is a shortage of electrons. Therefore, we conclude that there are 9 electrons missing (in short).

### Final Answer:
The conductor has 9 electrons in short.

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