A body has `-80` micro coulomb of charge. Number of additional electrons in it will be

Options

A. `8 xx 10^(-5)`
B. `80 xx 10^(-17)`
C. `5 xx 10^(14)`
D. `1.28 xx 10^(-17)`

Answer

To solve the problem of finding the number of additional electrons in a body with a charge of -80 microcoulombs, we can follow these steps:

### Step 1: Understand the given charge
The charge given is -80 microcoulombs. We need to convert this into coulombs for our calculations.

\[ -80 \, \text{microcoulombs} = -80 \times 10^{-6} \, \text{coulombs} \]

### Step 2: Know the charge of a single electron
The charge of a single electron (e) is approximately:

\[ e = 1.6 \times 10^{-19} \, \text{coulombs} \]

### Step 3: Use the formula for quantized charge
The total charge (Q) can be expressed in terms of the number of electrons (n) using the formula:

\[ Q = n \times e \]

Since the charge is negative, we can write:

\[ -80 \times 10^{-6} = n \times (-1.6 \times 10^{-19}) \]

### Step 4: Solve for n
To find the number of additional electrons (n), we rearrange the equation:

\[ n = \frac{Q}{e} = \frac{-80 \times 10^{-6}}{-1.6 \times 10^{-19}} \]

### Step 5: Perform the calculation
Now, we can calculate the value of n:

\[ n = \frac{80 \times 10^{-6}}{1.6 \times 10^{-19}} = \frac{80}{1.6} \times 10^{13} = 50 \times 10^{13} = 5 \times 10^{14} \]

### Conclusion
Thus, the number of additional electrons in the body is:

\[ n = 5 \times 10^{14} \]

### Final Answer
The number of additional electrons in the body is \(5 \times 10^{14}\).

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