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The electric field near a conducting sur...

The electric field near a conducting surface having a uniform surface charge denstiy `sigma` is given by

A

(a) `(sigma)/(epsi_(0))` and is parallel to the surface

B

(b) `(2 sigma)/(epsi_(0))`

C

(c) `(sigma)/(epsi_(0))` and is normal to the surface

D

(d) `(2 sigma)/(epsi_(0))` and is normal to the surface

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The correct Answer is:
To solve the problem of finding the electric field near a conducting surface with a uniform surface charge density \( \sigma \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: We have a conducting surface with a uniform surface charge density \( \sigma \). We need to determine the electric field \( E \) near this surface. 2. **Choosing a Gaussian Surface**: To apply Gauss's law, we will consider a Gaussian surface. A suitable choice is a cylindrical Gaussian surface that straddles the conducting surface. This surface will have one flat face inside the conductor and one flat face outside. 3. **Applying Gauss's Law**: According to Gauss's law, the electric flux \( \Phi_E \) through a closed surface is equal to the charge enclosed \( Q \) divided by the permittivity of free space \( \epsilon_0 \): \[ \Phi_E = \frac{Q}{\epsilon_0} \] The electric flux \( \Phi_E \) is given by: \[ \Phi_E = E \cdot A \] where \( E \) is the electric field and \( A \) is the area of the Gaussian surface. 4. **Calculating the Charge Enclosed**: The charge \( Q \) enclosed by the Gaussian surface can be calculated using the surface charge density \( \sigma \): \[ Q = \sigma \cdot A \] 5. **Setting Up the Equation**: Substituting the expression for \( Q \) into Gauss's law gives: \[ E \cdot A = \frac{\sigma \cdot A}{\epsilon_0} \] 6. **Solving for the Electric Field \( E \)**: We can cancel \( A \) from both sides (assuming \( A \neq 0 \)): \[ E = \frac{\sigma}{\epsilon_0} \] 7. **Direction of the Electric Field**: The electric field \( E \) is directed perpendicular to the surface of the conductor and away from the surface if the charge is positive. ### Final Answer: The electric field near a conducting surface having a uniform surface charge density \( \sigma \) is given by: \[ E = \frac{\sigma}{\epsilon_0} \]
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