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What is the magnitude of a point charge ...

What is the magnitude of a point charge due to which the electric field `30cm` away the magnitude `2`?
`[1//4 pi epsilon_(0)=9xx10^(9)Nm^(2)//C^(2)]`

A

`2 xx 10^(-11) C`

B

`3 xx 10^(-11) C`

C

`5 xx 10^(-11) C`

D

`9 xx 10^(-11) C`

Text Solution

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The correct Answer is:
A
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The electric field due to a charge at a distance of 3 m from it is 500 NC^(-1) . The magnitude of the charge is [(1)/(4 pi epsi_(0)) = 9 xx 10^(9) N - m^(2)//C^(2)]

Three particles, each having a charge of 10 mu C are placed at the coners of an equilateral triangle of side 10 cm . The electrostatic potential energy of the system is (Given (1)/(4pi epsilon_(0)) = 9 xx 10^(9)N-m^(2)//C^(2))

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Four idenbtial charges +50 mu C each are placed, one at each corner of a square of side 2 m . How much external energy is required to bring another charge of +50 mu C from infinity to the centre of the square (Given (1)/(4pi epsilon_(0)) = 9 xx 10^(9)(Nm^(2))/(C^(2)))

Two point charges 100 mu C and 5 mu C are placed at points A and B respectively with AB = 40 cm . The work done by external froce in displacing the charge 5 mu C from B to C, where BC = 30 cm , angle ABC = (pi)/(2) and (1)/(4pi epsilon_(0)) = 9 xx 10^(9)Nm^(2)//C^(2)

A slab of a material of dielectric constaant 2 is placed between two identical parallel plates. One of the plates carries total charge density +2mC/ m^(2) and the other plate carries total charge density -4mC/ m^(2) the magnitude of electric field inside the dielectric in (in 10^(11)N//C ) Take epsi_(0)=(80)/(9)xx10^(-12)Nm^(2)//C^(2) )

An electric bulb of power 30piW has an efficiency of 10% and it can be assumed to behave like a point source of light. At a distance of 3 m from the bulb, the peak value of the electric field in the light produced by the bulb is ["Take "epsilon_(0)~~9xx10^(-12)C^(2)N^(-1)m^(-2)]

A large charged metal sheet is placed in a uniform electric field, perpendicular to the electric field lines. After placing the sheet into the field, the electric field on the left side of the sheet is E_1 = 5 xx 10^5 Vm^(-1) and on the right it is E_2 = 3 xx 10^5 V m^(-1) . The sheet experiences a net electric force of 0.08 N. Find the area of one face of the sheet. Assume the external field to remain constant after introducing the large sheet. Use (1/(4piepsilon_0)) = 9 xx 10^(9) Nm^(2)C^(-2)

A hollow sphere of radius 0.1 m has a charge of 5 xx10^(-8) C . The potential at a distance of 5 cm from the centre of the sphere is (1/(4pi epsi_(0))=9xx10^(9) Nm^(2) C^(-2))

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