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A dipole of electric dipole moment p is ...

A dipole of electric dipole moment p is placed in a uniform electric field of strength E. If `theta` is the angle between positive direction of p and E, then the potential energy of the electric dipole is largest when `theta` is

A

`(pi)/(4)`

B

`(pi)/(2)`

C

`pi`

D

zero

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AI Generated Solution

The correct Answer is:
To determine the angle at which the potential energy of an electric dipole in a uniform electric field is maximized, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Electric Dipole Moment**: An electric dipole consists of two equal and opposite charges separated by a distance. The dipole moment \( \mathbf{p} \) is defined as \( \mathbf{p} = q \cdot \mathbf{d} \), where \( q \) is the charge and \( \mathbf{d} \) is the vector pointing from the negative charge to the positive charge. 2. **Potential Energy of the Dipole**: The potential energy \( U \) of an electric dipole in a uniform electric field \( \mathbf{E} \) is given by the formula: \[ U = -\mathbf{p} \cdot \mathbf{E} \] This can also be expressed in terms of the angle \( \theta \) between the dipole moment \( \mathbf{p} \) and the electric field \( \mathbf{E} \): \[ U = -pE \cos \theta \] 3. **Maximizing Potential Energy**: To find the angle \( \theta \) that maximizes the potential energy \( U \), we need to minimize \( \cos \theta \) since \( U \) is negative of \( pE \cos \theta \). 4. **Finding the Minimum Value of Cosine**: The cosine function \( \cos \theta \) has a minimum value of -1. This occurs when: \[ \cos \theta = -1 \] 5. **Determining the Corresponding Angle**: The angle \( \theta \) for which \( \cos \theta = -1 \) is: \[ \theta = 180^\circ \quad \text{or} \quad \theta = \pi \text{ radians} \] 6. **Conclusion**: Therefore, the potential energy of the electric dipole is largest when \( \theta \) is \( 180^\circ \) or \( \pi \) radians. ### Final Answer: The potential energy of the electric dipole is largest when \( \theta = 180^\circ \) or \( \theta = \pi \) radians. ---
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