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A small part of dl length is removed fro...


A small part of `dl` length is removed from a ring having charge per unit length `lamda`. Find electric field at centre due to remaining ring.

A

zero

B

`(-lambda dl)/(4 pi epsi_(0)a^(2))`

C

infinity

D

`(lambda)/(4 pi epsi_(0)dl)`

Text Solution

Verified by Experts

The correct Answer is:
B
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