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Charge q(2) of mass m revolves around a ...

Charge `q_(2)` of mass m revolves around a stationary charge `q_(1)` in a circulare orbit of radius r. The orbital periodic time of `q_(2)` would be

A

`[(4 pi^(2) mr^(3))/(k q_(1)q_(2))]^(1//2)`

B

`[(k q_(1) q_(2))/(4 pi^(2) mr^(3))]^(1//2)`

C

`[(4 pi^(2)mr^(4))/(k q_(1) q_(2))]^(1//2)`

D

`[(4 pi^(2) mr^(2))/(k q_(1) q_(2))]^(1//2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the orbital periodic time of charge \( q_2 \) revolving around a stationary charge \( q_1 \), we can follow these steps: ### Step 1: Identify the forces acting on the charge \( q_2 \) The charge \( q_2 \) experiences an electrostatic force due to the charge \( q_1 \), which acts as the centripetal force required for circular motion. ### Step 2: Write the expression for the electrostatic force The electrostatic force \( F \) between two point charges is given by Coulomb's law: \[ F = \frac{k \cdot |q_1 \cdot q_2|}{r^2} \] where \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the magnitudes of the charges, and \( r \) is the distance between them. ### Step 3: Set the electrostatic force equal to the centripetal force For circular motion, the centripetal force \( F_c \) required to keep the charge \( q_2 \) in orbit is given by: \[ F_c = m \cdot \omega^2 \cdot r \] where \( m \) is the mass of the charge \( q_2 \) and \( \omega \) is the angular velocity. Setting the electrostatic force equal to the centripetal force, we have: \[ \frac{k \cdot |q_1 \cdot q_2|}{r^2} = m \cdot \omega^2 \cdot r \] ### Step 4: Rearrange the equation to solve for \( \omega^2 \) Rearranging the equation gives: \[ \omega^2 = \frac{k \cdot |q_1 \cdot q_2|}{m \cdot r^3} \] ### Step 5: Find \( \omega \) Taking the square root of both sides, we find: \[ \omega = \sqrt{\frac{k \cdot |q_1 \cdot q_2|}{m \cdot r^3}} \] ### Step 6: Calculate the time period \( T \) The time period \( T \) of one complete revolution is related to the angular velocity \( \omega \) by the formula: \[ T = \frac{2\pi}{\omega} \] Substituting the expression for \( \omega \): \[ T = \frac{2\pi}{\sqrt{\frac{k \cdot |q_1 \cdot q_2|}{m \cdot r^3}}} \] ### Step 7: Simplify the expression for \( T \) This can be simplified as follows: \[ T = 2\pi \sqrt{\frac{m \cdot r^3}{k \cdot |q_1 \cdot q_2|}} \] ### Final Expression Thus, the orbital periodic time \( T \) of charge \( q_2 \) is: \[ T = 2\pi \sqrt{\frac{m \cdot r^3}{k \cdot |q_1 \cdot q_2|}} \]
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