Home
Class 12
PHYSICS
If 10^(10) electrons are acquired by a b...

If `10^(10)` electrons are acquired by a body every second, the time required for the body to get a total charge of C will be

A

2h

B

2 days

C

2 yr

D

20 yr

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the time required for a body to acquire a total charge of 1 coulomb when it acquires \(10^{10}\) electrons every second, we can follow these steps: ### Step 1: Calculate the charge acquired per second The charge of a single electron is approximately \(1.6 \times 10^{-19}\) coulombs. Therefore, the total charge acquired by the body in one second when it acquires \(10^{10}\) electrons is calculated as follows: \[ q = n \cdot e = 10^{10} \cdot (1.6 \times 10^{-19}) \] Calculating this gives: \[ q = 1.6 \times 10^{-9} \text{ coulombs} \] ### Step 2: Set up the equation for total charge We need to find the time \(t\) required to accumulate a total charge \(Q\) of 1 coulomb. The relationship between charge, current, and time is given by: \[ Q = q \cdot t \] Where: - \(Q\) = total charge (1 coulomb) - \(q\) = charge acquired per second (\(1.6 \times 10^{-9}\) coulombs) - \(t\) = time in seconds ### Step 3: Rearranging the equation to find time Rearranging the equation to solve for time \(t\): \[ t = \frac{Q}{q} \] Substituting the values we have: \[ t = \frac{1 \text{ coulomb}}{1.6 \times 10^{-9} \text{ coulombs}} \] ### Step 4: Calculate the time in seconds Calculating this gives: \[ t = \frac{1}{1.6 \times 10^{-9}} \approx 0.625 \times 10^{9} \text{ seconds} \] ### Step 5: Convert seconds to years To convert seconds into years, we use the following conversions: - 1 minute = 60 seconds - 1 hour = 60 minutes = \(60 \times 60 = 3600\) seconds - 1 day = 24 hours = \(24 \times 3600 = 86400\) seconds - 1 year = 365 days = \(365 \times 86400 = 31,536,000\) seconds Now, we convert seconds into years: \[ t \text{ (in years)} = \frac{0.625 \times 10^{9} \text{ seconds}}{31,536,000 \text{ seconds/year}} \] Calculating this gives: \[ t \approx 19.8 \text{ years} \approx 20 \text{ years} \] ### Final Answer The time required for the body to acquire a total charge of 1 coulomb is approximately **20 years**. ---
Promotional Banner

Topper's Solved these Questions

  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Assertion and Reason|15 Videos
  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Match the columns|5 Videos
  • ELECTROSTATICS

    DC PANDEY ENGLISH|Exercise Check point 1.5|20 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITORS

    DC PANDEY ENGLISH|Exercise (C) Chapter exercises|50 Videos
  • GRAVITATION

    DC PANDEY ENGLISH|Exercise All Questions|135 Videos

Similar Questions

Explore conceptually related problems

If 10^(9) electrons move out of a body to another body every second, then the time required to get a total charge of 1 C on the other body is

If a body gives out 10^(9) electrons every second, how much time required to get a total charge of 1 C from it ?

Wat is the charge acquired by a body when one million electrons are transferred to it.

A number of K-40 atoms explode in human body every second. The number of

Every second, human body converts carbon-14 atoms into C-12 atoms

How many electrons must be removed from a piece of metal to give it a positive charge of 1.0 xx 10^(-7)C

Starting from rest a body moves with uniform acceleration and acquires a velocity v after n seconds. Then its displacement in the last two seconds is

In case of electronic current the charge flows from negatively charged body to the Positively charged body. The body which is at higher potential is :

If a charge on the body is 1 nC , then how many electrons are present on the body?

If a body cools down from 80^(@) C to 60^(@) C in 10 min when the temperature of the surrounding of the is 30^(@) C . Then, the temperature of the body after next 10 min will be

DC PANDEY ENGLISH-ELECTROSTATICS-Taking it together
  1. The distance between the two charges 25 mu C and 36 muC is 11 cm. At w...

    Text Solution

    |

  2. The electric field at a point due to an electric dipole, on an axis in...

    Text Solution

    |

  3. If 10^(10) electrons are acquired by a body every second, the time req...

    Text Solution

    |

  4. ABC is an equilateral triangle. Charges -2q are placed at each corner....

    Text Solution

    |

  5. Two equally charged, indentical metal spheres A and B repel each other...

    Text Solution

    |

  6. Two point charges +10^(-7) C and -10^(-7)C are placed at A and B 20 cm...

    Text Solution

    |

  7. Infinite charges of magnitude q each are lying at x= 1,2,4,8….meter on...

    Text Solution

    |

  8. Two copper balls, each weighing 10 g are kept in air 10 cm apart. If o...

    Text Solution

    |

  9. A wooden block performs SHM on a frictionless surface with frequency, ...

    Text Solution

    |

  10. A thin conducting ring of radius R is given a charge +Q, Fig. The ele...

    Text Solution

    |

  11. Four point +ve charges of same magnitude(Q) are placed at four corners...

    Text Solution

    |

  12. A hollow cylinder has a charge qC within it. If phi is the electric fl...

    Text Solution

    |

  13. The adjacent diagram shows a charge +Q held on an insulating support S...

    Text Solution

    |

  14. An infinitely long thin straight wire has uniform linear charge densit...

    Text Solution

    |

  15. Two concentric conducting thin spherical shells A andB having radii rA...

    Text Solution

    |

  16. Two identical charged spheres suspended from a common point by two mas...

    Text Solution

    |

  17. An electron is released from the bottom plate A as shown in the figure...

    Text Solution

    |

  18. Charge q is uniformly distributed over a thin half ring of radius R. T...

    Text Solution

    |

  19. In the given figure two tiny conducting balls of identical mass m and ...

    Text Solution

    |

  20. Two small spheres of masses M(1)and M(2) are suspended by weightless i...

    Text Solution

    |