If a charge on the body is `1 nC`, then how many electrons are present on the body?

Options

A. `1.6xx10^(19)`
B. `6.25xx10^(9)`
C. `6.25xx10^(27)`
D. `6.25xx10^(28)`

Answer

To find the number of electrons present on a body with a charge of 1 nC (nano coulomb), we can follow these steps:

### Step 1: Understand the given charge
The charge on the body is given as:
\[ q = 1 \, \text{nC} = 1 \times 10^{-9} \, \text{C} \]

### Step 2: Know the charge of a single electron
The charge of a single electron is:
\[ e = 1.6 \times 10^{-19} \, \text{C} \]

### Step 3: Use the formula to find the number of electrons
The total charge \( q \) can be expressed in terms of the number of electrons \( n \) and the charge of a single electron \( e \):
\[ q = n \cdot e \]
From this, we can rearrange the formula to find \( n \):
\[ n = \frac{q}{e} \]

### Step 4: Substitute the values into the equation
Substituting the values of \( q \) and \( e \):
\[ n = \frac{1 \times 10^{-9} \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} \]

### Step 5: Perform the division
Calculating the above expression:
\[ n = \frac{1 \times 10^{-9}}{1.6 \times 10^{-19}} = \frac{1}{1.6} \times 10^{10} \]
\[ n \approx 0.625 \times 10^{10} \]
\[ n = 6.25 \times 10^{9} \]

### Step 6: Conclusion
Thus, the number of electrons present on the body is:
\[ n \approx 6.25 \times 10^{9} \]

### Final Answer
The answer is \( 6.25 \times 10^{9} \) electrons.

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