An alpha particle with kinetic energy `10 Me V` is heading toward a stationary tin nucleus of atomic number 50. Calculate the distance of closest approach (Fig . 3.23).
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An alpha particle with kinetic energy 10 Me V is heading toward a stationary tin nuclcus of atomic number 50. Calculate the distance of closest approach (Fig . 3.23). .

Define the distance of closest approach. An alpha -particle of kinetic enegy 'K' is bombarded on a thin gold foil. The distance of the closest approach is 'r' . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ?

(a) Define the distance of closest approach. A alpha -particle of kinetic energy K is bombarded on a thin gld foil. The distance of the closest approach is r_(a) . What will be the distance of closest approach for an alpha -particle of double the kinetic energy ? (b) Show that the radius of the orbit of an electron in hydrogen atoms varies as n^(2) , where n is the principal quantum number of the atom.

An alpha - particle moving with initial kinetic energy K towards a nucleus of atomic number z approaches a distance 'd' at which it reverse its direction. Obtain the expression for the distance of closest approach 'd' in terms of the kinetic energy of alpha - particle K.

The distance of the closest approach of an alpha particle fired at a nucleus with kinetic of an alpha particle fired at a nucleus with kinetic energy K is r_(0) . The distance of the closest approach when the alpha particle is fired at the same nucleus with kinetic energy 2K will be

In one experiment , a proton having kinetic energy of 1 eV is accelerated through a potential difference of 3 V. In another experiment, an alpha -particle having initial kinetic energy 20 eV is retarded by a potential difference of 2 V. Calculate the ratio of de-Broglie wavelengths of proton and alpha - particle.

An alpha - particle after passing through a potential difference of V volts collides with a nucleus . If the atomic number of the nucleus is Z then the distance of closest approach of alpha – particle to the nucleus will be

If an alpha -particle is incident directly towards a nucleus then it will stop when the distance between them is the distance of closest approach. Which of these is correct?

A particle moving with kinetic energy = 3J makes an elastic head-on collision with a stationary particle which has twice its mass. During the impact :-

In a Geiger- Marsden experiment, calculate the distance of closest approach to the nucleus of Z=80, when an alpha particle of 8 Me V energy impinges on it before it comes momentarily to rest and reverses its direction. How will the distance of closest approach be affected when the kinetic energy of the alpha- particle is doubled ?