Two capacitors of capacitances `C_(1)=2muF` and `C_(2)=8muF` are connected in series and the resulting combination is connected across a `300V` battery. Calculate the charge, potential difference and energy stored in the capacitor separately.

Two capacitors with capacitances C_(1) and C_(2) are connected in series. Find the resultant capacitance.

Two capacitor of capacitance 4.0muF and 6.0muF' are connected in series with a battery of 20 V . Find the energy supplied by the battery .

Two capacitors of capacitance of 6 muF and 12 muF are connected in series with a battery. The voltage across the 6 muF capacitor is 2V. Compute the total battery voltage.

A capacitor of capacitance 1muF is connected in parallel with a resistance 10Omega and the combination is connected across the terminals of a battery of EMF 50 V and internal resistance 1Omega . The potential difference across the capacitor at steady state is (in Volt)

Three capacitors of 2 muF, 3 muF and 6 muF are joined in series and the combination is charged by means of a 24 volt battery. The potential difference between the plates of the 6 muF capacitor is

Three capacitors of capacitances 1muF,2muF and 4muF are connected first in a series combination, and then in parallel combination. The ratio of their equivalent capacitances will be

Two capacitances of capacity C_(1) and C_(2) are connected in series and potential difference V is applied across it. Then the potential difference across C_(1) will be

If potential difference across 3muF is 4V, then total energy stored in all capacitors is

Two capacitors of 10muF and 20 muF are connected in series with a 30 V battery. The charge on the capacitors will be, respectively

Two capacitrors of 2 muF and 4 muF are connected in parallel. A third capacitor of 6 muF is connected in series. The combaination is connected across a 12 V battery. The voltage across 2 mu F capacitor is