Two plates are `2cm` apart, a potential difference of `10` volt is applied between them, the electric field between the plates is

Options

A. `20 "NC"^(-1)`
B. `500 "NC"^(-1)`
C. `5 "NC"^(-1)`
D. `250 "NC"^(-1)`h

Answer

To find the electric field (E) between two plates that are separated by a distance (d) and have a potential difference (V) applied across them, we can use the formula:

\[ E = \frac{V}{d} \]

### Step-by-Step Solution:

1. **Identify the given values:**
- Potential difference (V) = 10 volts
- Distance between the plates (d) = 2 cm

2. **Convert the distance from centimeters to meters:**
- Since 1 cm = 0.01 m, we convert 2 cm to meters:
\[ d = 2 \, \text{cm} = 2 \times 0.01 \, \text{m} = 0.02 \, \text{m} \]

3. **Substitute the values into the formula:**
- Now, we can substitute the values of V and d into the electric field formula:
\[ E = \frac{V}{d} = \frac{10 \, \text{V}}{0.02 \, \text{m}} \]

4. **Calculate the electric field:**
- Performing the division:
\[ E = \frac{10}{0.02} = 500 \, \text{N/C} \]

5. **Final Answer:**
- The electric field between the plates is \( 500 \, \text{N/C} \).