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The electrostatic potential of a uniform...

The electrostatic potential of a uniformly charged thin spherical shell of charge Q and radius R at a distance `r` from the centre

A

`(Q)/(4 pi epsilon_(0)r)` for points outside and `(Q)/(4pi epsilon_(0)R)` for points inside the shell

B

`(Q)/(4pi epsilon_(0)e)` for both points inside nad outside the shell

C

zero for points outside and `(Q)/(4pi epsilon_(0)r)` for points inside the shell

D

zero for both points inside and outside the shell

Text Solution

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The correct Answer is:
To find the electrostatic potential \( V \) of a uniformly charged thin spherical shell of charge \( Q \) and radius \( R \) at a distance \( r \) from the center, we can analyze two cases: when the point is inside the shell and when it is outside the shell. ### Step 1: Understand the Concept of Electrostatic Potential Electrostatic potential \( V \) at a point in space due to a charge distribution is defined as the work done in bringing a unit positive charge from infinity to that point. ### Step 2: Analyze the Case for Points Inside the Shell (\( r < R \)) For a uniformly charged thin spherical shell, the electric field inside the shell is zero. This can be derived from Gauss's law, which states that the electric field inside a uniformly charged shell is zero because the contributions from all parts of the shell cancel out. Since the electric field \( E = 0 \) inside the shell, the potential \( V \) remains constant throughout the interior of the shell. The potential inside the shell is equal to the potential at the surface of the shell. ### Step 3: Calculate the Potential at the Surface of the Shell The potential at the surface of the shell (at distance \( R \)) can be calculated using the formula for the potential due to a point charge: \[ V(R) = \frac{kQ}{R} \] where \( k \) is Coulomb's constant. ### Step 4: Conclude for Points Inside the Shell Thus, for any point inside the shell (\( r < R \)): \[ V = \frac{kQ}{R} \] ### Step 5: Analyze the Case for Points Outside the Shell (\( r \geq R \)) For points outside the shell, the shell behaves like a point charge located at its center. Therefore, we can use the same formula for the potential due to a point charge: \[ V(r) = \frac{kQ}{r} \] where \( r \) is the distance from the center of the shell. ### Step 6: Conclude for Points Outside the Shell Thus, for any point outside the shell (\( r \geq R \)): \[ V = \frac{kQ}{r} \] ### Final Summary - For \( r < R \) (inside the shell): \[ V = \frac{kQ}{R} \] - For \( r \geq R \) (outside the shell): \[ V = \frac{kQ}{r} \]
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