The work done in bringing a `20` coulomb charge from point `A` to point `B` for disatnce `0.2 m` is `2 J`. The potential difference between the two points will be (in volt)

Options

A. 0.2
B. 8
C. 0.1
D. 0.4

Answer

To find the potential difference between two points A and B when a charge is moved, we can use the relationship between work done, charge, and potential difference. The formula we will use is:

\[ V = \frac{W}{Q} \]

where:
- \( V \) is the potential difference (in volts),
- \( W \) is the work done (in joules),
- \( Q \) is the charge (in coulombs).

### Step-by-Step Solution:

1. **Identify the given values**:
- Work done \( W = 2 \, \text{J} \)
- Charge \( Q = 20 \, \text{C} \)

2. **Substitute the values into the formula**:
\[ V = \frac{W}{Q} = \frac{2 \, \text{J}}{20 \, \text{C}} \]

3. **Calculate the potential difference**:
\[ V = \frac{2}{20} = 0.1 \, \text{V} \]

4. **Conclusion**:
The potential difference between points A and B is \( 0.1 \, \text{V} \).

### Final Answer:
The potential difference between the two points will be \( 0.1 \, \text{V} \).

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