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Separation between the plates of a paral...

Separation between the plates of a parallel plate capacitor is `d` and the area of each plates is `A`. When a slab of material of dielectric constant `k` and thickness `t(t lt d)` is introduced between the plates. Its capacitance becomes

A

`(epsilon_(0)A)/(d+t(1-(1)/(K)))`

B

`(epsilon_(0)A)/(d+t(1+(1)/(K)))`

C

`(epsilon_(0)A)/(d-t(1-(1)/(K)))`

D

`(epsilon_(0)A)/(d-t(1+(1)/(K)))`

Text Solution

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The correct Answer is:
To find the capacitance of a parallel plate capacitor when a dielectric slab is introduced, we can follow these steps: ### Step 1: Understand the Configuration We have a parallel plate capacitor with: - Plate separation: \( d \) - Area of each plate: \( A \) - Dielectric slab thickness: \( t \) (where \( t < d \)) - Dielectric constant of the slab: \( k \) ### Step 2: Determine the Effective Capacitance When the dielectric slab is introduced, the capacitor can be thought of as two capacitors in series: 1. The first capacitor has a dielectric slab of thickness \( t \) and dielectric constant \( k \). 2. The second capacitor has air (or vacuum) with thickness \( d - t \). ### Step 3: Calculate Capacitance of Each Section 1. **Capacitance of the dielectric section**: \[ C_1 = \frac{k \epsilon_0 A}{t} \] where \( \epsilon_0 \) is the permittivity of free space. 2. **Capacitance of the air section**: \[ C_2 = \frac{\epsilon_0 A}{d - t} \] ### Step 4: Combine the Capacitances Since \( C_1 \) and \( C_2 \) are in series, the total capacitance \( C \) is given by: \[ \frac{1}{C} = \frac{1}{C_1} + \frac{1}{C_2} \] Substituting the expressions for \( C_1 \) and \( C_2 \): \[ \frac{1}{C} = \frac{t}{k \epsilon_0 A} + \frac{d - t}{\epsilon_0 A} \] ### Step 5: Simplify the Expression Combine the fractions: \[ \frac{1}{C} = \frac{t + (d - t)k}{k \epsilon_0 A} \] \[ \frac{1}{C} = \frac{d k}{k \epsilon_0 A} \] ### Step 6: Solve for Capacitance Taking the reciprocal gives: \[ C = \frac{k \epsilon_0 A}{d k + (d - t)} \] ### Final Expression Thus, the capacitance of the capacitor with the dielectric slab inserted is: \[ C = \frac{A \epsilon_0}{\frac{d - t}{k} + t} \]
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