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The distance between the circular plates...

The distance between the circular plates of a parallel plate condenser 40 mm in diameter, in order to have same capacity as a sphere of radius 1 m is

A

0.01 mm

B

0.1 mm

C

1.0 mm

D

10 mm

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The correct Answer is:
To find the distance between the circular plates of a parallel plate capacitor that has the same capacitance as a sphere of radius 1 m, we can follow these steps: ### Step 1: Understand the given data - Diameter of the parallel plate capacitor (d) = 40 mm - Radius of the sphere (R) = 1 m ### Step 2: Convert the diameter to radius The radius (r) of the parallel plate capacitor is half of the diameter: \[ r = \frac{d}{2} = \frac{40 \text{ mm}}{2} = 20 \text{ mm} = 20 \times 10^{-3} \text{ m} \] ### Step 3: Write the formula for capacitance of a parallel plate capacitor The capacitance (C1) of a parallel plate capacitor is given by: \[ C_1 = \frac{\epsilon_0 A}{d} \] where \(A\) is the area of the plates and \(d\) is the distance between the plates. The area \(A\) of the circular plates is: \[ A = \pi r^2 \] Substituting this into the capacitance formula gives: \[ C_1 = \frac{\epsilon_0 \pi r^2}{d} \] ### Step 4: Write the formula for capacitance of a sphere The capacitance (C2) of an isolated sphere is given by: \[ C_2 = 4 \pi \epsilon_0 R \] ### Step 5: Set the capacitances equal to each other Since we want the capacitance of the parallel plate capacitor to be equal to that of the sphere: \[ C_1 = C_2 \] This leads to: \[ \frac{\epsilon_0 \pi r^2}{d} = 4 \pi \epsilon_0 R \] ### Step 6: Simplify the equation We can cancel \(\epsilon_0\) and \(\pi\) from both sides: \[ \frac{r^2}{d} = 4R \] ### Step 7: Solve for \(d\) Rearranging the equation gives: \[ d = \frac{r^2}{4R} \] ### Step 8: Substitute the values Substituting \(r = 20 \times 10^{-3} \text{ m}\) and \(R = 1 \text{ m}\): \[ d = \frac{(20 \times 10^{-3})^2}{4 \times 1} \] Calculating \( (20 \times 10^{-3})^2 \): \[ (20 \times 10^{-3})^2 = 400 \times 10^{-6} \text{ m}^2 \] Now substituting back: \[ d = \frac{400 \times 10^{-6}}{4} = 100 \times 10^{-6} \text{ m} \] ### Step 9: Convert to mm To convert meters to millimeters: \[ d = 100 \times 10^{-6} \text{ m} = 0.1 \text{ mm} \] ### Final Answer The distance \(d\) between the circular plates of the parallel plate capacitor is: \[ \boxed{0.1 \text{ mm}} \]
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