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The distance of the closest approach of an alpha particle fired at a nucleus with kinetic of an alpha particle fired at a nucleus with kinetic energy K is `r_(0)`. The distance of the closest approach when the `alpha` particle is fired at the same nucleus with kinetic energy 2K will be

A

`4 r_(0)`

B

`r_(0)/2`

C

`r_(0)/4`

D

`2r_(0)`

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The correct Answer is:
B
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