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A battery charges a parallel plate capac...

A battery charges a parallel plate capacitor of thickness `(d)` so that an energy `[U_(0)]` is stored in the system. A slab of dielectric constant `(K)` and thickness `(d)` is then introduced between the plates of the capacitor. The new energy of the system is given by

A

`K U_(0)`

B

`K^(2) U_(0)`

C

`U_(0)/K`

D

`U_(0)/K^(2)`

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The correct Answer is:
To solve the problem step by step, we need to analyze the situation before and after the introduction of the dielectric slab in the parallel plate capacitor. ### Step 1: Understand the Initial Conditions Initially, we have a parallel plate capacitor with: - Thickness = \(d\) - Initial energy stored = \(U_0\) The energy stored in a capacitor is given by the formula: \[ U = \frac{1}{2} C V^2 \] where \(C\) is the capacitance and \(V\) is the voltage across the capacitor. ### Step 2: Determine the Initial Capacitance The capacitance \(C\) of a parallel plate capacitor is given by: \[ C = \frac{\varepsilon_0 A}{d} \] where: - \(\varepsilon_0\) is the permittivity of free space - \(A\) is the area of the plates - \(d\) is the separation between the plates ### Step 3: Relate Initial Energy to Capacitance and Voltage From the initial energy stored \(U_0\), we can express it as: \[ U_0 = \frac{1}{2} C V^2 \] This can be rearranged to find \(CV^2\): \[ CV^2 = 2U_0 \] ### Step 4: Introduce the Dielectric Slab When a dielectric slab with dielectric constant \(K\) and thickness \(d\) is introduced between the plates, the new capacitance \(C'\) becomes: \[ C' = K \cdot C \] ### Step 5: Calculate the New Energy Stored The new energy \(U'\) stored in the capacitor after the dielectric is introduced can be expressed as: \[ U' = \frac{1}{2} C' V^2 \] Substituting \(C'\) into the equation: \[ U' = \frac{1}{2} (K \cdot C) V^2 \] ### Step 6: Substitute \(CV^2\) from Initial Conditions Now, we can substitute \(CV^2\) from the earlier step: \[ U' = \frac{1}{2} (K \cdot C) V^2 = K \cdot \frac{1}{2} C V^2 = K \cdot U_0 \] ### Final Result Thus, the new energy of the system after introducing the dielectric slab is: \[ U' = K \cdot U_0 \]
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