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An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal to

A

1

B

`sqrt(M_(p)/M_(e))`

C

`sqrt(M_(e)/M_(p))`

D

`M_(e)/M_(p)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the motion of the electron and the proton in a uniform electric field. Let's break it down step by step. ### Step 1: Understanding the Forces Both the electron and the proton experience an electric force when placed in a uniform electric field \( E \). The force \( F \) acting on each particle can be expressed as: - For the electron: \[ F_e = eE \] - For the proton: \[ F_p = eE \] where \( e \) is the charge of the electron and proton (equal in magnitude). ### Step 2: Calculating Accelerations The acceleration \( a \) of each particle can be found using Newton's second law, \( F = ma \): - For the electron: \[ a_e = \frac{F_e}{m_e} = \frac{eE}{m_e} \] - For the proton: \[ a_p = \frac{F_p}{m_p} = \frac{eE}{m_p} \] ### Step 3: Using the Kinematic Equation Since both particles start from rest and travel the same distance \( s \), we can use the kinematic equation: \[ s = \frac{1}{2} a t^2 \] For the electron: \[ s = \frac{1}{2} a_e t_1^2 \implies s = \frac{1}{2} \left(\frac{eE}{m_e}\right) t_1^2 \] For the proton: \[ s = \frac{1}{2} a_p t_2^2 \implies s = \frac{1}{2} \left(\frac{eE}{m_p}\right) t_2^2 \] ### Step 4: Setting the Equations Equal Since both expressions for \( s \) are equal, we can set them equal to each other: \[ \frac{1}{2} \left(\frac{eE}{m_e}\right) t_1^2 = \frac{1}{2} \left(\frac{eE}{m_p}\right) t_2^2 \] The \( \frac{1}{2} \) and \( eE \) terms cancel out: \[ \frac{t_1^2}{m_e} = \frac{t_2^2}{m_p} \] ### Step 5: Rearranging for the Ratio Rearranging the equation gives: \[ \frac{t_2^2}{t_1^2} = \frac{m_p}{m_e} \] Taking the square root of both sides yields: \[ \frac{t_2}{t_1} = \sqrt{\frac{m_p}{m_e}} \] ### Final Answer Thus, the ratio \( \frac{t_2}{t_1} \) is nearly equal to: \[ \frac{t_2}{t_1} = \sqrt{\frac{m_p}{m_e}} \]
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