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Two identical capacitors are first conne...

Two identical capacitors are first connected in series and then in parallel. The ratio of equivalent capacitance is

A

`1 : 1`

B

`1 : 2`

C

`1 : 3`

D

`1 : 4`

Text Solution

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The correct Answer is:
To solve the problem of finding the ratio of equivalent capacitance when two identical capacitors are connected in series and then in parallel, we can follow these steps: ### Step 1: Define the Capacitance of Each Capacitor Let the capacitance of each identical capacitor be \( C \). ### Step 2: Calculate the Equivalent Capacitance for Series Connection When two capacitors are connected in series, the formula for the equivalent capacitance \( C_{eq, series} \) is given by: \[ \frac{1}{C_{eq, series}} = \frac{1}{C_1} + \frac{1}{C_2} \] Since both capacitors have the same capacitance \( C \): \[ \frac{1}{C_{eq, series}} = \frac{1}{C} + \frac{1}{C} = \frac{2}{C} \] Thus, the equivalent capacitance for the series connection is: \[ C_{eq, series} = \frac{C}{2} \] ### Step 3: Calculate the Equivalent Capacitance for Parallel Connection When the same two capacitors are connected in parallel, the formula for the equivalent capacitance \( C_{eq, parallel} \) is: \[ C_{eq, parallel} = C_1 + C_2 \] Again, since both capacitors have the same capacitance \( C \): \[ C_{eq, parallel} = C + C = 2C \] ### Step 4: Find the Ratio of Equivalent Capacitances Now, we need to find the ratio of the equivalent capacitance in series to that in parallel: \[ \text{Ratio} = \frac{C_{eq, series}}{C_{eq, parallel}} = \frac{\frac{C}{2}}{2C} \] Simplifying this gives: \[ \text{Ratio} = \frac{C}{2} \cdot \frac{1}{2C} = \frac{1}{4} \] ### Step 5: Express the Ratio The ratio of the equivalent capacitance when the capacitors are in series to when they are in parallel is: \[ \text{Ratio} = 1 : 4 \] Thus, the final answer is that the ratio of equivalent capacitance of capacitors in series to that in parallel is \( 1 : 4 \). ---
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