An electron beam has an aperture of `2mm^(2)`. A total of `7xx10^(16)` electrons flow through any perpendicular cross-section per second. Calculate the current density in the electron beam.

An electorn beam has an aperture 1.0 mm^(2) . A totak of 6.0xx10^(16) electons go through any perpendicular cross section per second. Find(a) the current and (b) the current density in the beam.

A total of 6.0 xx 10^(16) electrons pass through any cross - section of a conducting wire per second. Find the current.

If 10^(6) electrons/s are flowing through an area of cross section of 10^(-4) m^(2) then the current will be:-

10^(23) electrons passed from left to rigth normally through a cross section in 1s. Average current through the cross section is

A flow of 10^(7) electrons per second in a conducing wire constitutes a current of .

The diameter of a copper wire is 2mm, if a steady current of 6.25 A is caused by 8.5xx10^(28) //m^(3) electrons flowing throught it. Calculate the drift velocity of condu ction electrons.

The length of a current-carrying cylindrical conductor is l, its area of cross-section is A, the number density of free electrons in it is n, and the drift velocity of electrons in it is v_d . The number of electrons passing through a particular cross-section of the conductor per unit time is given by:

A flow of (10^12) electron per minute in a conducting wire constitutes a current of

A flow of 10^12 electrons per minute in a conducting wire constitutes a current of

A stready current i is flowing through a conductor of uniform cross-section. Any segment of the conductor has