The reading on a high resistance voltmeter when a cell is connected across it is 3 V. When the terminals of the cell are also connected to a resistance of 4 `Omega`, then the voltmeter reading drops to `1.2` V. Find the internal resistance of the cell.

Write any two factors on which internal resistance of a cell depends . The reading on a high resistance voltmeter , when a cell is connected across it , is 2.0 V . When the terminals of the cell are also connected to a resistance of 3 Omega as shown in the circuit , the voltmeter reading drops to 1.5 V . Find the internal resistance of the cell.

Write any two factors on which internal resistance of a cell depends .The reading on a high resistance voltmer,where a cell is connected across it , is 2.2 V. When the terminals of the cell are also connected to a resistance of 5 Omega as shown in the circuit , the voltmeter reading drops to 1.8 V .Find the interval resistance of the cell.

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is

A cell has an emf 1.5V. When connected across an external resistance of 2Omega , the terminal potential difference falls to 1.0V. The internal resistance of the cell is:

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

In a potentiometer experiment it is found that no current passes through the galvanometer when the terminals of the cell are connected across 0.52 m of the potentiometer wire. If the cell is shunted by a resistance of 5Omega balance is obtained when the cell connected across 0.4m of the wire. Find the internal resistance of the cell.

A high resistance voltmeter measures the potential difference across a battery to be 9-0 V. On connecting a 24 2 resistor across the terminals of the battery, the voltmeter reads 7.2 V. Calculate the internal resistance of the battery.

The cell has an emf of 2 V and the internal resistance of this cell is 0.1 Omega , it is connected to resistance of 3.9 Omega , the voltage across the cell will be

When an ammeter of negligible internal resistance is inserted in series with circuit, it reads 1 A . When a voltmeter of very large resistance is connected across R_(1) , it reads 3 V . But when the points A and B are short-circuited by a conducting wire, then the voltmetre measures 10.5 V across the battery. The internal resistance of the battery is equal to