Two identical cells of emf 1.5 V each joined in paralllel provide supply to an external circuit consisting of two resistances of `7 Omega` each joined in parallel. A very high resistance voltmeter reads the terminal voltage of cells to be 1.4 V. Calculate the internal resistance of each cell.

Four identical cells each of emf 2V, are joined in parallel providing supply of current to external circuit consisting of two 15 Omega resistors joined in parallel. The terminal voltage of the cells ae read by an ideal voltmeter is 1.6V. Calculate the internal resistance of each cell.

A cell supplies a current of 1.2 A through two resistors each of 2 Omega connected in parallel. When the resistors are connected in series, it supplies a current of 0.4 A. Calculate : the internal resistance,

A cell has an emf 1.5V. When connected across an external resistance of 2Omega , the terminal potential difference falls to 1.0V. The internal resistance of the cell is:

A cell of emf E is connected across a resistance R. The potential difference between the terminals of the cell is found to be V. The internal resistance of the cell must be -

A battery of e.m.f 3 V supplies current through a circuit in which the resistance can be changed. A high resistance voltmeter is connected across the battery. When the current is 1.5 A, the voltmeter reads 2.7 V. Find the internal resistance of the battery.

If the reading of the ideal voltmeter shown in the circuit is 2V the internal resistance of the two identical cells is

Fig. shows two resistors A of 4 Omega and B of 6 Omega joined in series to a battery of e.m.f. 12 V and internal resistance 2 Omega . Calculate : the terminal voltage of the battery,

In the circuit shown in fig. the cell has emf 10V and internal resistance 1 Omega

n identical cells each of emf 6 V , connected in series with an external resistor of 5Omega , carry a current of 10A . If two cells are connected wrongly in series with the same external resistor, the current flowing through the cells will be 8A. Find the value of n and r the internal resistance of each cell.

The emf of a daniel cell is 1.08 V. When the terminals of the cell are connected to resistance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then , the internal resistance of the cell is