A cell can be balanced against `110 cm` and `100 cm` of potentiometer wire, respectively with and without being short circuited through a resistance of `10 Omega`. Its internal resistance is

A Daniel cell is balanced on 125 cm length of a potentiometer wire. Now the cells is short-circuited by a resistance 2 ohm and the balance is obtained at 100 cm . The internal resistance of the Dainel cell is

For the given circuit, If internal resistance of cell is 1.5 Omega , then

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

The internal resistance of a 2.1 V cell which gives a current 0.2 A through a resistance of 10 Omega

The internal resistance of a 2.1 V cell which gives a current of 0.2A through a resistance of 10 Omega is

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is

A 20 m long potentiometer wire has a resistance of 20 Ohm. It is connected in series with a battery of emf 3V and resistance of 10 Omega . The internal resistance of cell is negligible. If the lenth can be read accurately up to 1 mm, the potentiometer can read voltage:

An experimental setup of verification of photoelectric effect is shown if Fig. The voltage across the electrodes is measured with the help of an ideal voltmeter, and which can be varied by moving jockey J on the potentiometer with wire. The battery used in potentiometer circuit is of 20 V and its internal resistance is 2 Omega . The resistance of 100 cm long potentiometer wire is 8 Omega . The photocurrent is measured with the help of an ideal ammeter. Two plates of potassium oxide of area 50 cm^2 at separation 0.5mm are used in the vacuum tube. Photocurrent in the circuit is very small, so we can treat the potentiometer circuit as an independent circuit. The wavelength of various colors is as follows: Q. It is found that ammeter current remains unchanged (2muA) even when the jockey is moved from the end P to the middle point of the potentiometer wire. Assuming that all the incident photons eject electrons and the power of the light incident is 4xx10^(-6) W. Then, the color of the incident light is

The e.m.f. of a standard cell balances across 150 cm length of a wire of potentiometer. When a resistance of 2Omega is connected as a shunt with the cell, the balance point is obtained at 100cm . The internal resistance of the cell is

A standerd cell emf 1.08 V is balance by the potential difference across 91 cm of a meter long wire applied by a cell of emf 2 V through a series resistor of resistance 2 Omega . The internal resistance of the cell is zero. Find the resistance per unit length of the potentiometer wire.