In a potentiometer arrangement, a cell of emf `2.25V` gives a balance point at `30.0` cm length of the wire. If the cell is replaced by another cell and the balance point shifts to `60.0` cm, then what is the emf of the second cell?

In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell ?

In a potentiometer arrangement , a cell of EMF 2 V gives a balance point at 40 cm length of the wire . If this cell is replaced by another cell and the balance point shifts to 60 cm , then the EMF of the second cell is

In a potentiometer arrangement, a cell of emf 1.5 V gives a balance point at 27 cm length of wire. If the cell is replaced by another cell and balance point shifts to 54 cm, the emf of the second cell is :

In a potentiometer arrangement a cell of emf 1.5 V gives a balance point at 30 cm length of wire. Now, when the cell is replaced by another celle , the balance point shifts to 50 cm. What is the emf of second cell ?

In a potentiometer a cell of emf 1.5V gives a balanced point 32cm length of the cell is replaced by another cell then the balance point shifts to 65.0cm the emf of second cell is

In a potentiometer arrangement a cell of emf 1.20 V given a balance point at 30 cm length of the wire. The cell a now replaced by another cell of unknown emf. The ratio of emfs of the two cells is 1.5 , calculate the difference in the balancing length of the potentiometer wire in the two cases

In potentiometer experiment, a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, then balancing length is found to be 40 cm. What is the emf of second cell ?

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is

is made of uniform material and cross-sectional area, and it has uniform resistance per unit length. The potential gradient depends upon the current in the wire. A potentiometer with a cell of emf 2 V and internal resistance 0.4 Omega is used across the wire AB . A standard cadmium cell of emf 1.02 V gives a balance point at 66 cm length of wire. The standard cell is then replaced by a cell of unknows emf e (internal resistance r ), and the balance. Point found similarly turns out to be 88 cm length of the wire. The length of potentiometer wire AB is 1 m . The reading of the potentiometer, if a 4V battery is used instead of e is

A Daniel cell is balanced on 125 cm length of a potentiometer wire. Now the cells is short-circuited by a resistance 2 ohm and the balance is obtained at 100 cm . The internal resistance of the Dainel cell is