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Drift velocity v(d) varies with the inte...

Drift velocity `v_(d)` varies with the intensity of electric field as per their relation

A

`v_(d)propE`

B

`v_(d)prop(1)/(E)`

C

`v_(d)="constant"`

D

`v_(d)propE^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the relationship between drift velocity \( v_d \) and the intensity of the electric field \( E \), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Drift Velocity**: Drift velocity \( v_d \) is the average velocity that charged particles, such as electrons, attain due to an electric field. 2. **Formula for Drift Velocity**: The drift velocity can be expressed using the formula: \[ v_d = \frac{eV}{mL \tau} \] where: - \( e \) is the charge of the electron, - \( V \) is the potential difference, - \( m \) is the mass of the electron, - \( L \) is the length of the conductor, - \( \tau \) is the relaxation time. 3. **Relating Potential Difference to Electric Field**: The potential difference \( V \) can be expressed in terms of the electric field \( E \) and the length \( L \) of the conductor: \[ V = E \cdot L \] 4. **Substituting into Drift Velocity Formula**: Substituting \( V \) into the drift velocity formula gives: \[ v_d = \frac{e(E \cdot L)}{mL \tau} \] 5. **Simplifying the Expression**: In the equation, the length \( L \) cancels out: \[ v_d = \frac{eE}{m \tau} \] 6. **Identifying the Relationship**: From the simplified equation, we can see that: \[ v_d \propto E \] This indicates that the drift velocity \( v_d \) is directly proportional to the electric field intensity \( E \) when \( e \), \( m \), and \( \tau \) are constants. 7. **Conclusion**: Therefore, the relationship between drift velocity and electric field intensity is: \[ v_d \text{ is directly proportional to } E \] ### Final Answer: The correct option is **Option 1: \( v_d \) is proportional to the electric field intensity \( E \)**.
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