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A student has 10 resistors of resistance...

A student has 10 resistors of resistance ‘ r ’. The minimum resistance made by him from given resistors is

A

10r

B

`(r)/(10)`

C

`(r)/(100)`

D

`(r)/(5)`

Text Solution

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The correct Answer is:
To find the minimum resistance that can be made using 10 resistors, each with a resistance of \( r \), we will connect all the resistors in parallel. Here’s a step-by-step solution: ### Step 1: Understanding Resistance in Parallel When resistors are connected in parallel, the formula for the equivalent resistance \( R_{eq} \) is given by: \[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots + \frac{1}{R_n} \] ### Step 2: Applying the Formula Since all 10 resistors have the same resistance \( r \), we can denote the resistance of each resistor as \( R_1 = R_2 = \ldots = R_{10} = r \). Therefore, we can rewrite the equation for the equivalent resistance as: \[ \frac{1}{R_{eq}} = \frac{1}{r} + \frac{1}{r} + \frac{1}{r} + \ldots + \frac{1}{r} \quad (\text{10 times}) \] ### Step 3: Simplifying the Equation This simplifies to: \[ \frac{1}{R_{eq}} = \frac{10}{r} \] ### Step 4: Finding the Equivalent Resistance To find \( R_{eq} \), we take the reciprocal of both sides: \[ R_{eq} = \frac{r}{10} \] ### Conclusion Thus, the minimum resistance that can be obtained by connecting all 10 resistors in parallel is: \[ \boxed{\frac{r}{10}} \]
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