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A metal plate weighting 750g is to be el...

A metal plate weighting 750g is to be electroplated with 0.05% of its weight of silver. If a current of 0.8A is used. Find the time needed for depositing the required weight of silver. `E.C.E.` of silver is `11.18xx10^(-7)kgC^(-1)`.

A

5 min 32 s

B

6 min 37 s

C

4 min 16 s

D

6 min 10 s

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The correct Answer is:
To solve the problem of electroplating a metal plate with silver, we will follow these steps: ### Step 1: Calculate the weight of silver to be deposited The weight of silver to be deposited (W) is given as 0.05% of the weight of the metal plate. \[ W = \frac{0.05}{100} \times \text{Weight of the plate} \] Given that the weight of the plate is 750 grams, we convert it to kilograms: \[ W = \frac{0.05}{100} \times 0.75 \text{ kg} = 0.000375 \text{ kg} \] ### Step 2: Use Faraday's Law to find the time required According to Faraday's law, the weight of the material deposited is given by the formula: \[ W = Z \times I \times t \] Where: - \(W\) = weight of silver deposited (in kg) - \(Z\) = electrochemical equivalent of silver \(= 11.18 \times 10^{-7} \text{ kg/C}\) - \(I\) = current (in A) - \(t\) = time (in seconds) We need to rearrange this formula to find time \(t\): \[ t = \frac{W}{Z \times I} \] ### Step 3: Substitute the known values into the equation Now we can substitute the values we have: \[ t = \frac{0.000375 \text{ kg}}{(11.18 \times 10^{-7} \text{ kg/C}) \times (0.8 \text{ A})} \] ### Step 4: Calculate the denominator First, calculate the denominator: \[ Z \times I = 11.18 \times 10^{-7} \times 0.8 = 8.944 \times 10^{-7} \text{ kg/C} \] ### Step 5: Calculate the time Now substitute this back into the equation for \(t\): \[ t = \frac{0.000375}{8.944 \times 10^{-7}} \approx 419.3 \text{ seconds} \] ### Step 6: Convert seconds to minutes To convert seconds into minutes, we divide by 60: \[ t \approx \frac{419.3}{60} \approx 6.99 \text{ minutes} \approx 6 \text{ minutes and } 59 \text{ seconds} \] ### Final Answer Thus, the time needed for depositing the required weight of silver is approximately **6 minutes and 59 seconds**. ---
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