A carbon film resistor has cololur code green, black, violet, gold. The value of the resistor is

Options

A. `50M Omega`
B. `500M Omega`
C. `500 pm 5%M Omega`
D. `500 pm 10%M Omega`

Answer

To find the value of the carbon film resistor with the color code green, black, violet, and gold, we can follow these steps:

### Step 1: Identify the Color Code Values
Using the standard resistor color code chart (often referred to as the BBROY chart), we can identify the values associated with each color:
- **Green**: 5 (first digit)
- **Black**: 0 (second digit)
- **Violet**: 7 (multiplier, which means \(10^7\))
- **Gold**: Tolerance of ±5%

### Step 2: Construct the Resistor Value
Now, we can construct the resistor value using the identified digits and the multiplier:
- The first digit is 5 (from green).
- The second digit is 0 (from black).
- Therefore, the base value is 50 (from the first two digits).
- The multiplier is \(10^7\) (from violet).

So, the value of the resistor can be calculated as:
\[ \text{Resistor Value} = 50 \times 10^7 \, \Omega = 500000000 \, \Omega = 500 \, \text{M}\Omega \]

### Step 3: Determine the Tolerance
The gold band indicates the tolerance of the resistor, which is ±5%. This means the actual resistance can vary by 5% from the nominal value.

### Final Result
Thus, the value of the resistor is:
\[ 500 \, \text{M}\Omega \, \pm \, 5\% \]