An electron revolves in a circule at the rate of `10^(19)` rounds per second. The rquivlent current is `(e=1.6xx10^(-19)C)`

Options

A. `1.0 A`
B. `1.6A`
C. `2.0A`
D. `2.6A`

Answer

To find the equivalent current due to an electron revolving in a circle at a rate of \(10^{19}\) rounds per second, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Current**:
Current (I) is defined as the charge (Q) flowing per unit time (t). Mathematically, this is expressed as:
\[ I = \frac{Q}{t} \]

2. **Identify the Charge of an Electron**:
The charge of a single electron is given as:
\[ e = 1.6 \times 10^{-19} \text{ C} \]

3. **Determine the Frequency of Revolution**:
The electron revolves at a frequency (f) of:
\[ f = 10^{19} \text{ rounds per second} \]

4. **Calculate the Time Period (T)**:
The time period (T) is the time taken for one complete revolution and is the reciprocal of the frequency:
\[ T = \frac{1}{f} = \frac{1}{10^{19}} \text{ seconds} \]

5. **Substitute Values into the Current Formula**:
Now, substituting the values of charge and time into the current formula:
\[ I = \frac{Q}{T} = \frac{1.6 \times 10^{-19} \text{ C}}{1 \times 10^{-19} \text{ s}} \]

6. **Perform the Calculation**:
Simplifying the expression gives:
\[ I = 1.6 \text{ A} \]

### Final Answer:
The equivalent current due to the electron revolving in a circle is:
\[ I = 1.6 \text{ A} \]