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Two bulbs when connected in parallel to ...

Two bulbs when connected in parallel to a source take 60 W each, the power consumed, when they are connected in series with the same source is

A

15 W

B

30 W

C

60 W

D

120 W

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The correct Answer is:
To solve the problem, we need to find the power consumed by two bulbs when they are connected in series after knowing their power consumption when connected in parallel. ### Step-by-Step Solution: 1. **Identify the Power Consumption in Parallel:** Each bulb consumes 60 W when connected in parallel. Therefore, we have: \[ P_1 = 60 \, \text{W} \quad \text{and} \quad P_2 = 60 \, \text{W} \] 2. **Calculate the Equivalent Resistance of Each Bulb:** The power consumed by a resistor (bulb) can be expressed using the formula: \[ P = \frac{V^2}{R} \] Rearranging this gives us: \[ R = \frac{V^2}{P} \] Since both bulbs have the same power rating, we can denote their resistances as \( R_1 \) and \( R_2 \): \[ R_1 = R_2 = \frac{V^2}{60} \] 3. **Calculate the Total Resistance in Series:** When connected in series, the total resistance \( R_{total} \) is the sum of the individual resistances: \[ R_{total} = R_1 + R_2 = \frac{V^2}{60} + \frac{V^2}{60} = \frac{2V^2}{60} = \frac{V^2}{30} \] 4. **Calculate the Power in Series:** The power consumed in series can be calculated using the formula: \[ P_{total} = \frac{V^2}{R_{total}} \] Substituting the expression for \( R_{total} \): \[ P_{total} = \frac{V^2}{\frac{V^2}{30}} = 30 \, \text{W} \] 5. **Conclusion:** Therefore, the power consumed when the two bulbs are connected in series is: \[ P_{total} = 30 \, \text{W} \] ### Final Answer: The power consumed when the bulbs are connected in series is **30 W**.
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