A charged particle projected in a magnetic field
`B=(3hati+4hatj)xx10^-2T`
The acceleration of the particle is found to be
`a=(xhati+2hatj)m/s^2`
find the value of `x`

A charged particle moves in a uniform magnetic field B=(2hati-3hatj) T

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If a particle of charge 1μC is projected into a magnetic field vecB = (2hati + yhatj- zhatk) T with a velocity vecV = (4hati+2hatj - 6hatk)ms^(-1) , then it passes undeviated. If it is now projected with a velocity vecV = hati + hatj , then find the force experienced by it?

A charged particle carrying charge 1 mu C is moving with velocity (2 hati + 3hati + 4hatk) ms^(-1) . If an external magnetic field of (5 hati + 3hatj - 6hatk) xx 10^(-3)T exists in the region where the particle is moving then the force on the particle is vecF xx 10^(-9)N . The vector vecF is :

Velocity and acceleration of a particle are v=(2 hati-4 hatj) m/s and a=(-2 hati+4 hatj) m/s^2 Which type of motion is this?

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In magnetic field B=(2hati+3hatj) T, velocity of a charged particle is given in table-1. Corresponding magnetic force is given in table-2. Match the two tables.