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A charge particle travels along a straig...

A charge particle travels along a straight line with a speed v in region where both electric field E and magnetic field b are present.It follows that

A

`|E|=|B|` and the two field are perpendicular

B

`|E|=v|B|` and the two field are perpendicular

C

`|B|=v|E|` and the two field are parallel

D

`|B|=v|E|` and the two fields are perpendicular

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To solve the problem of a charged particle traveling along a straight line in the presence of both electric and magnetic fields, we can follow these steps: ### Step-by-Step Solution 1. **Identify the Forces Acting on the Charged Particle**: - The charged particle experiences two forces: the electric force (\( F_E \)) and the magnetic force (\( F_B \)). - The electric force is given by: \[ F_E = Q \cdot E \] - The magnetic force is given by: \[ F_B = Q \cdot (v \times B) \] 2. **Set Up the Condition for Straight-Line Motion**: - For the charged particle to move in a straight line, the net force acting on it must be zero: \[ F_E + F_B = 0 \] - This implies: \[ Q \cdot E + Q \cdot (v \times B) = 0 \] 3. **Simplify the Equation**: - Since \( Q \) is not zero, we can divide the entire equation by \( Q \): \[ E + (v \times B) = 0 \] - Rearranging gives: \[ E = - (v \times B) \] 4. **Analyze the Magnitudes**: - Taking magnitudes on both sides, we have: \[ |E| = |v| \cdot |B| \cdot \sin(\theta) \] - Here, \( \theta \) is the angle between the velocity vector \( v \) and the magnetic field vector \( B \). 5. **Determine the Relationship Between the Fields**: - For the charged particle to move in a straight line, the electric field \( E \) must be equal in magnitude to the magnetic force, which implies that the two fields are perpendicular to each other: \[ |E| = |v| \cdot |B| \] - This indicates that the electric field \( E \) is perpendicular to the magnetic field \( B \). 6. **Conclusion**: - Therefore, we conclude that the magnitude of the electric field \( E \) is equal to the product of the speed \( v \) of the charged particle and the magnitude of the magnetic field \( B \), and the two fields are perpendicular. ### Final Answer: The correct relationship is: \[ |E| = |v| \cdot |B| \quad \text{and the fields are perpendicular.} \]
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