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Two wires of same length are shaped into...

Two wires of same length are shaped into a square and a circle. If they carry same current, ratio of the magnetic moment is

A

`2:pi`

B

`pi:2`

C

`pi:4`

D

`4:pi`

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The correct Answer is:
To find the ratio of the magnetic moments of two wires shaped into a square and a circle, we can follow these steps: ### Step 1: Determine the length of the wire Let the length of the wire be \( L \). ### Step 2: Calculate the side length of the square For a square, the perimeter is given by: \[ \text{Perimeter} = 4A \] where \( A \) is the side length of the square. Since the length of the wire is \( L \), we have: \[ L = 4A \implies A = \frac{L}{4} \] ### Step 3: Calculate the area of the square The area \( A_s \) of the square is: \[ A_s = A^2 = \left(\frac{L}{4}\right)^2 = \frac{L^2}{16} \] ### Step 4: Calculate the magnetic moment of the square The magnetic moment \( M_s \) for a current \( I \) flowing in the square loop is given by: \[ M_s = I \cdot A_s = I \cdot \frac{L^2}{16} = \frac{I L^2}{16} \] ### Step 5: Calculate the radius of the circle For a circle, the circumference is given by: \[ \text{Circumference} = 2\pi R \] where \( R \) is the radius of the circle. Since the length of the wire is \( L \), we have: \[ L = 2\pi R \implies R = \frac{L}{2\pi} \] ### Step 6: Calculate the area of the circle The area \( A_c \) of the circle is: \[ A_c = \pi R^2 = \pi \left(\frac{L}{2\pi}\right)^2 = \pi \cdot \frac{L^2}{4\pi^2} = \frac{L^2}{4\pi} \] ### Step 7: Calculate the magnetic moment of the circle The magnetic moment \( M_c \) for a current \( I \) flowing in the circular loop is given by: \[ M_c = I \cdot A_c = I \cdot \frac{L^2}{4\pi} = \frac{I L^2}{4\pi} \] ### Step 8: Find the ratio of the magnetic moments Now, we can find the ratio of the magnetic moment of the square to that of the circle: \[ \text{Ratio} = \frac{M_s}{M_c} = \frac{\frac{I L^2}{16}}{\frac{I L^2}{4\pi}} = \frac{4\pi}{16} = \frac{\pi}{4} \] ### Conclusion Thus, the ratio of the magnetic moment of the square to that of the circle is: \[ \frac{\pi}{4} \]
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