Find the quantity of heat required to convert 40 g of ice at `-20^(@)`C into water at `20^(@)`C. Given `L_(ice) = 0.336 xx 10^(6) J/kg.` Specific heat of ice = 2100 J/kg-K
Specific heat of water = 4200 J/kg-K

Explanation

To find the quantity of heat required to convert 40 g of ice at -20°C into water at 20°C, we will break the process into three steps:

1. Heating the ice from -20°C to 0°C.
2. Melting the ice at 0°C to water at 0°C.
3. Heating the water from 0°C to 20°C.

### Step 1: Heating the Ice from -20°C to 0°C

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