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suppose you want to cool 0.25 kg of cola...

suppose you want to cool 0.25 kg of cola (mostly water ), at `25^(@)C` by adding ice initially at `-20^(@)C`. How much ice should you add so that the final temperature will be `0^(@)C` with all the ice melt? Neglect the heat capacity of the container. specific heat of ice is` 2000 Jkg^(-1)K^(-1)`. [take specific heat of cola `4160 Jkg^(-1)K^(-1)`.]

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To solve the problem of how much ice should be added to cool 0.25 kg of cola from 25°C to 0°C with all the ice melting, we can follow these steps: ### Step 1: Calculate the heat lost by the cola The heat lost by the cola as it cools from 25°C to 0°C can be calculated using the formula: \[ Q_{\text{cola}} = m_{\text{cola}} \cdot c_{\text{cola}} \cdot \Delta T_{\text{cola}} \] ...
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