How much heat is required to convert 8.0 g of ice at `-15^@C` to steam at `100^@C`? (Given, `c_(ice) = 0.53 cal//g.^@C, L_f = 80 cal//g and L_v = 539 cal//g, `
and `c_(water) = 1 cal//g.^@C)` .

Explanation

To solve the problem of how much heat is required to convert 8.0 g of ice at -15°C to steam at 100°C, we need to consider the different stages of the phase change and temperature change. The process can be broken down into four steps:

### Step 1: Heating the Ice from -15°C to 0°C
We will first calculate the heat required to raise the temperature of the ice from -15°C to 0°C.

**Formula:**
\[ Q_1 = m \cdot c_{\text{ice}} \cdot \Delta T \]

...