An iron boiler is 1 cm thick and has a heating area `2.5 m^(2)`. The two surface of the boiler are at `230^(@)C` and `100^(@)C` respectively. If the latent heat of the steam is `540 kcal kg^(-1)` and thermal conductivity of iron is `1.6xx10^(-2)K cal s^(-1) m^(-1)K^(-1)`, then how much water will be evaporated into steam per minute ?

Explanation

To solve the problem, we need to calculate the amount of water that will be evaporated into steam per minute using the heat conducted through the iron boiler. Here are the steps:

### Step 1: Identify the given values
- Thickness of the boiler (b) = 1 cm = 0.01 m
- Heating area (A) = 2.5 m²
- Temperature difference (ΔT) = 230°C - 100°C = 130°C
- Latent heat of steam (L) = 540 kcal/kg
- Thermal conductivity of iron (k) = 1.6 × 10^(-2) kcal/s·m·K
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