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One end of a rod of length 20cm is inser...

One end of a rod of length `20cm` is inserted in a furnace at `800K` The sides of the rod are covered with an insulating material and the other end emits radiation like a black body. The temperature of this end is `750K` in the steady state The temperature of the surrounding air is `300K` Assuming radiation to be the only important mode of energy transfer between the surrounding and the open end of the rod, find the thermal conductivity of the rod Stefan's constant `sigma = 6.0 xx 10^(-8) W m^(-2) K^(-4)` .

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To find the thermal conductivity of the rod, we can follow these steps: ### Step 1: Understand the Problem We have a rod of length \( L = 20 \, \text{cm} = 0.2 \, \text{m} \) with one end in a furnace at \( T = 800 \, \text{K} \) and the other end at \( T_1 = 750 \, \text{K} \). The surrounding air temperature is \( T_0 = 300 \, \text{K} \). The rod is insulated on the sides, and the end emits radiation like a black body. ### Step 2: Write the Heat Conduction Equation The heat conducted through the rod can be expressed as: \[ ...
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One end of a rod length 20cm is inserted in a furnace at 800K. The sides of the rod are covered with an insulating material and the other end emits radiation like a blackbody. The temperature of this end is 750K in the steady state. The temperature of the surrounding air is 300K. Assuming radiation to be the only important mode of energy transfer between the surrounding and the open end of the rod, find the thermal conductivity of the rod. Stefan constant sigma=6.0xx10^(-1)Wm^(-2)K^(-4) .

One end of a rod length 20cm is inserted in a furnace at 800K . The sides of the rod are covered with an insulating material and the other end emits radiation like a blackbody. The temperature of this end is 750K in the steady state. The temperature of the surrounding air is 300K . Assuming radiation to be the only important mode of energy transfer between the surrounding and the open end of the rod, find the thermal conductivity of the rod. Stefan constant sigma=6.0xx10^(-1)Wm^(-2)K^(-4) .

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