A body cools in 10 min from `60^(@)`C to `40^(@)`C and to `42.5^(@)`C in 7.5 min. Find the temperature of the surroundings.

Explanation

To solve the problem, we will use Newton's Law of Cooling, which states that the rate of change of temperature of an object is proportional to the difference between its temperature and the ambient temperature (temperature of the surroundings).

### Step-by-Step Solution:

1. **Identify the given values:**
- Initial temperature \( T_1 = 60^\circ C \)
- Final temperature after 10 minutes \( T_2 = 40^\circ C \)
- Time \( t = 10 \) minutes
...