When a particle is projected from the surface of earth, its mechanical energy and angular momentum about centre of earth at all time is constant .
A particle mass m is projected from the surface of earth with velocity `v_(0)` at angle `theta` with horizontal. Suppose h be the maximum height of particle from surface of earth and v its speed at that point then v is

Options

A. `=(v_(0)^(2) sin^(2) theta)/(2g)`
B. `gt(v_(0)^(2) sin^(2) theta)/(2g)`
C. `lt(v_(0)^(2) sin^(2) theta)/(2g)`
D. can be greater than or less than `(v_(0)^(2) sin^(2) theta)/(2g)`

Answer

B