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Dimensions of underset("electric flux")o...

Dimensions of `underset("electric flux")overset("magnetic flux") to` are

A

`(L-T^(-1))`

B

`(TL^(-1))`

C

`(L^(3)r^(2)A^(-2))`

D

`(M^(0)L^(0)T^(0))`

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The correct Answer is:
To find the dimensions of the ratio of magnetic flux to electric flux, we will follow these steps: ### Step 1: Determine the dimension of magnetic flux Magnetic flux (Φ_m) is given by the formula: \[ Φ_m = B \cdot A \] where \( B \) is the magnetic field and \( A \) is the area. The dimension of area \( A \) is: \[ [A] = L^2 \] To find the dimension of the magnetic field \( B \), we can use the relationship between force, charge, and magnetic field: \[ F = Q \cdot v \cdot B \] Rearranging gives: \[ B = \frac{F}{Q \cdot v} \] The dimensions of force \( F \) are: \[ [F] = M L T^{-2} \] The dimension of charge \( Q \) is: \[ [Q] = I \cdot T \] The dimension of velocity \( v \) is: \[ [v] = L T^{-1} \] Substituting these into the equation for \( B \): \[ [B] = \frac{M L T^{-2}}{(I \cdot T)(L T^{-1})} = \frac{M L T^{-2}}{I L T^{-1}} = \frac{M}{I T} \] Now substituting back into the magnetic flux formula: \[ [Φ_m] = [B] \cdot [A] = \left(\frac{M}{I T}\right) \cdot L^2 = \frac{M L^2}{I T} \] ### Step 2: Determine the dimension of electric flux Electric flux (Φ_e) is given by: \[ Φ_e = E \cdot A \] where \( E \) is the electric field. Using the relationship between force, charge, and electric field: \[ F = Q \cdot E \] Rearranging gives: \[ E = \frac{F}{Q} \] Substituting the dimensions: \[ [E] = \frac{M L T^{-2}}{I T} = \frac{M L}{I T^2} \] Now substituting back into the electric flux formula: \[ [Φ_e] = [E] \cdot [A] = \left(\frac{M L}{I T^2}\right) \cdot L^2 = \frac{M L^3}{I T^2} \] ### Step 3: Calculate the ratio of magnetic flux to electric flux Now we find the ratio: \[ \frac{Φ_m}{Φ_e} = \frac{\frac{M L^2}{I T}}{\frac{M L^3}{I T^2}} \] This simplifies to: \[ \frac{Φ_m}{Φ_e} = \frac{M L^2}{I T} \cdot \frac{I T^2}{M L^3} = \frac{L^2 T^2}{L^3} = \frac{T^2}{L} = T^2 L^{-1} \] ### Final Answer The dimensions of the ratio of magnetic flux to electric flux are: \[ T^2 L^{-1} \]
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