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Two coils have self-inductance L(1)=4mHa...

Two coils have self-inductance `L_(1)=4mHandL_(2)=1mH` respectively. The currents in the two coils are increased at the same rate. At a certain instant of time both coils are given the same power. If `I_(1)andI_(2)` are the currents in the two coils at that instant of time respectively, then the value of `(I_(1))/(I_(2))` is

A

`1//8`

B

`1//4`

C

`1//2`

D

`1`

Text Solution

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The correct Answer is:
B
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