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The electric current in a circuit is giv...

The electric current in a circuit is given by
i=3t
Here, t is in second and I in ampere. The rms current for the period to=0 to t=1 s is

A

3A

B

2A

C

`sqrt3`A

D

`3sqrt3A`

Text Solution

AI Generated Solution

The correct Answer is:
To find the RMS (Root Mean Square) current for the given current function \( i(t) = 3t \) over the time interval from \( t = 0 \) to \( t = 1 \) second, we can follow these steps: ### Step 1: Understand the formula for RMS current The RMS current is given by the formula: \[ I_{rms} = \sqrt{\frac{1}{T} \int_0^T i^2(t) \, dt} \] where \( T \) is the period of the current and \( i(t) \) is the instantaneous current. ### Step 2: Identify the function and limits In this case, the function is \( i(t) = 3t \) and the limits for integration are from \( t = 0 \) to \( t = 1 \) second. ### Step 3: Calculate \( i^2(t) \) First, we need to square the current function: \[ i^2(t) = (3t)^2 = 9t^2 \] ### Step 4: Set up the integral for \( i^2(t) \) Now we set up the integral: \[ \int_0^1 i^2(t) \, dt = \int_0^1 9t^2 \, dt \] ### Step 5: Evaluate the integral To evaluate the integral: \[ \int 9t^2 \, dt = 9 \cdot \frac{t^3}{3} = 3t^3 \] Now, we evaluate it from 0 to 1: \[ \left[ 3t^3 \right]_0^1 = 3(1^3) - 3(0^3) = 3 - 0 = 3 \] ### Step 6: Calculate the RMS current Now, substitute the value of the integral back into the RMS formula: \[ I_{rms} = \sqrt{\frac{1}{1} \cdot 3} = \sqrt{3} \] ### Final Answer Thus, the RMS current for the period from \( t = 0 \) to \( t = 1 \) second is: \[ I_{rms} = \sqrt{3} \text{ A} \]
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