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A copper rod of mass m slides under grav...

A copper rod of mass `m` slides under gravity on two smooth parallel rails `l` distance apart set at an angle `theta` to the horizontal. At the bottom, the rails are joined by a resistance `R`.

There is a uniform magnetic field perpendicular to the plane of the rails. the terminal valocity of the rod is

A

`(mgR cos theta)/(B^(2)I^(2))`

B

`(mgR sin theta)/(B^(2)I^(2))`

C

`(mgR tan theta)/(B^(2)I^(2))`

D

`(mgR cos theta)/(B^(2)I^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
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