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A conducting rod AC of length 4l is rota...

A conducting rod `AC` of length `4l` is rotate about a point `O` in a uniform magnetic field `vecB` directed into the paper. `AO=l` and `OC=3l`. Then

A

`V_(A)-V_(0)=(Bomegal^(2))/(2)`

B

`V_(0)-V_(C)=(9)/(2)Bomegal^(2)`

C

`V_(A)-V_(C)=4Bomegal^(2)`

D

`V_(C)-V_(0)=(9)/(2)Bomegal^(2)`

Text Solution

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The correct Answer is:
B, C
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